有时候需要使用使用php检查身份证号码是否正确
这就需要封装一个函数来实现。
下面这个函数说明了实现过程
/**
* 检查身份证号码
* 参数：$sfznum是15位或18位身份证号码，可选参数 $len 可以是15位号码。
* 返回值：失败返回FALSE，成功返回一个18位的身份证号
*/
private function checksfznum($sfznum, $len = 'both')
{
if (strlen ( $sfznum ) == 15 && $len == 'both') { //当$len不等于'both'时，15位号码无效
$truenum = substr ( $sfznum, 0, 6 ) . '19' . substr ( $sfznum, 6 ); //为返回18位号码作准备。
$preg = "/^[\\d]{8}((0[1-9])|(1[0-2]))((0[1-9])|([12][\\d])|(3[01]))[\\d]{3}$/";
} elseif (strlen ( $sfznum ) == 18) {
$truenum = substr ( $sfznum, 0, 17 );
$preg = "/^[\\d]{6}((19[\\d]{2})|(200[0-8]))((0[1-9])|(1[0-2]))((0[1-9])|([12][\\d])|(3[01]))[\\d]{3}[0-9xX]$/";
} else {
return false;
}
if (! preg_match ( $preg, $sfznum )) {
return false; //完成正则表达式检测
}
/*-----------以下计算第18位验证码-------------*/
$nsum = substr ( $truenum, 0, 1 ) * 7;
$nsum = $nsum + substr ( $truenum, 1, 1 ) * 9;
$nsum = $nsum + substr ( $truenum, 2, 1 ) * 10;
$nsum = $nsum + substr ( $truenum, 3, 1 ) * 5;
$nsum = $nsum + substr ( $truenum, 4, 1 ) * 8;
$nsum = $nsum + substr ( $truenum, 5, 1 ) * 4;
$nsum = $nsum + substr ( $truenum, 6, 1 ) * 2;
$nsum = $nsum + substr ( $truenum, 7, 1 ) * 1;
$nsum = $nsum + substr ( $truenum, 8, 1 ) * 6;
$nsum = $nsum + substr ( $truenum, 9, 1 ) * 3;
$nsum = $nsum + substr ( $truenum, 10, 1 ) * 7;
$nsum = $nsum + substr ( $truenum, 11, 1 ) * 9;
$nsum = $nsum + substr ( $truenum, 12, 1 ) * 10;
$nsum = $nsum + substr ( $truenum, 13, 1 ) * 5;
$nsum = $nsum + substr ( $truenum, 14, 1 ) * 8;
$nsum = $nsum + substr ( $truenum, 15, 1 ) * 4;
$nsum = $nsum + substr ( $truenum, 16, 1 ) * 2;
$yzm = 12 - $nsum % 11;
if ($yzm == 10){
$yzm = 'x';
} elseif ($yzm == 12) {
$yzm = '1';
} elseif ($yzm == 11) {
$yzm = '0';
}
/*----------18位验证码计算完成-------------*/
if (strlen ( $sfznum ) == 18) {
if (strtolower(substr($sfznum, 17, 1)) != $yzm)
return false;
}
return $truenum . $yzm;
}